Given #sintheta=-1, cottheta=0# to find the remaining trigonometric function? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Monzur R. Mar 26, 2017 See below Explanation: #sintheta=-1# #cottheta = 0# #costheta = sqrt(1-sin^2theta)=sqrt(1-(-1)^2)=sqrt0=0# #tantheta=sintheta/costheta=(-1)/0= "undefined"# #csctheta=1/sintheta=1/(-1)=-1# #sectheta=1/costheta=1/0= "undefined"# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 3510 views around the world You can reuse this answer Creative Commons License