Given that #(f \cdot g)(x) = (x+1)/2#, and #g(x) = 2x-1#, what is #f(x-3)#?

1 Answer
Sep 8, 2017

If #g(x)=2x-1#, #g^(-1) (x)=(x+1)/2#

After plugging #g^(-1) (x)# into first function, I found #f(x)=(x+3)/4#

Hence #f(x-3)=x/4#

Explanation:

1) I found #g^(-1) (x)#

2) I plugged #g^(-1) (x)# for finding #f(x)#

3) I plugged #x-3# in place of #x# for finding #f(x-3)#