Question

Given that `log_b(N^4)=8`, what is `log_b(1/N)`?

Answer 1

`-2`

Explanation:

`log_b(N^4)=4log_bN=8`. So, `log_bN=2`. And so,

`log_b(1/N)=log_b(N^(-1))=-log_bN=-2`