Question

Given the equation: `2Al + 3Cu_2 ->2Al^(3+) + 3Cu`. What is the reduction half-reaction?

Answer 1

`Cu^(2+) + 2e^(-) rarr Cu(s)`

Explanation:

And the oxidation reaction.........

`Al(s) rarr Al^(3+) + 3e^-`

And cross-multiplying to remove the electrons.........

`2Al(s) + 3Cu^(2+) rarr 2Al^(3+) + 2Cu(s)`

Is charge balanced? Is mass balanced?