Given the equation 6=-s+77, what is the value of 1+5(77-s)?

2 Answers
Oct 22, 2016

We want to first figure out what the value of s is, so let's do that.

If 6=-s+77, we can rearrange the formula to get s=71:

6=-s+77
6+s=77
s=71

Now that we know the value of s, we can substitute it into the formula 1+5(77-s).

Let's sub in s=71 and solve it.

1+5(77-71)
1+5(6)
1+30 =31

Oct 22, 2016

1+5(77-s)=31

Explanation:

The trick to reducing the solution work for this question is spotting that one is a part repeat of the other.

Let the unknown value be x then

x=1+5(77-s) ............Equation(1)
6=-s+77.................Equation(2)

Change the order of equation(2) giving

x=1+5(77-s)color(white)(.) ..........Equation(1)
6=77-s color(white)(.)......................Equation(2_a)color(red)(" "larr"part repeat"

Substitute for 77-s in Equation(1) using Equation(2_a)

So Equation(1) becomes:

x=1+5(77-s)" "->" "x=1+5(6)

x=31