Question

Given the equation `6=-s+77`, what is the value of `1+5(77-s)`?

Answer 1

We want to first figure out what the value of `s` is, so let's do that.

If `6=-s+77`, we can rearrange the formula to get `s=71`:

`6=-s+77`
`6+s=77`
`s=71`

Now that we know the value of `s`, we can substitute it into the formula `1+5(77-s)`.

Let's sub in `s=71` and solve it.

`1+5(77-71)`
`1+5(6)`
`1+30 =31`

Answer 2

`1+5(77-s)=31`

Explanation:

The trick to reducing the solution work for this question is spotting that one is a part repeat of the other.

Let the unknown value be `x` then

`x=1+5(77-s) ............Equation(1)`
`6=-s+77.................Equation(2)`

Change the order of equation(2) giving

`x=1+5(77-s)color(white)(.) ..........Equation(1)`
`6=77-s color(white)(.)......................Equation(2_a)color(red)(" "larr"part repeat"`

Substitute for `77-s` in Equation(1) using `Equation(2_a)`

So Equation(1) becomes:

`x=1+5(77-s)" "->" "x=1+5(6)`

`x=31`