Given the equation: Pb(SO4)2 + 4 LiNO3 --> Pb(NO3)4 + 2 Li2SO4, how many grams of lithium nitrate will be needed to make 250 grams of lithium sulfate, assuming that you have an adequate amount of lead (IV) sulfate to do the reaction? Thanks lots.?
If this reaction were to occur,
This at first glance looks like a double replacement (double displacement) reaction. However, a double replacement reaction does not occur unless one of the products is a solid precipitate, an insoluble gas, or water. In this case, none of those is a product. All of the compounds are aqueous.
This reaction will not actually occur. All you will have is a mixture of
However, I will work it out so you can see how a problem of this type is to be done.
Step 1: You need the molar masses of lithium nitrate and lithium sulfate.
You can calculate it or find it in a resource.
This type of problem follows the pattern:
Step 2: Convert mass of
Divide the mass of lithium sulfate by its molar mass.
I am including a couple of guard units to reduce rounding errors. I will round the final answer to two significant figures.
Step 3: Convert moles of
Multiply moles of
Step 4: Convert moles
Multiply the moles
This problem can be worked out all at once as follows.