Given the matrices #A=[(5,7),(-1,6), (3,-9)], B=[(8,3), (5,1), (4,4)], C=[(0,4),(-2,5), (7,-1)], D[(6,2), (9,0), (-3,0)]#, how do you find 6B-2A?

1 Answer
Narad T.
Nov 14, 2016

The answer is #=((38,4),(32,-6),(18,42))#

Explanation:

#A=((5,7),(-1,6),(3,-9))#

Therefore, #2A=2*((5,7),(-1,6),(3,-9))=((10,14),(-2,12),(6,-18))#

#B=((8,3),(5,1),(4,4))#

Therefore, #6B=6*((8,3),(5,1),(4,4))=((48,18),(30,6),(24,24))#

So, #6B-2A=((48,18),(30,6),(24,24))-((10,14),(-2,12),(6,-18))#

#= ((38,4),(32,-6),(18,42))#

Related questions
See all questions in Addition of Matrices
Impact of this question
1590 views around the world
You can reuse this answer
Creative Commons License