Question

Given the molar mass of the compound is 186.5 g and the empirical formula is C2H7, what is its molecular formula?

Answer 1

The molecular formula is always a multiple of the empirical formula.

Explanation:

So `(EF)_n = MF`. All we have to do is solve for `n`.

i.e. `(2xx12.011 + 7 xx 1.00794)_n*g*mol^(-1) = 186.5*g*mol^(-1)`. So solve for `n`, and then do the product `(C_2H_7) xx n` to give the molecular formula. Please repost the answer here.