Given this reaction: #CH_4 + 2O_2 -> CO_2 + H_2O#, 16 g of #CH_4# react with 64 g of #O_2#, producing 44 g of #CO_2#. How many grams of water are produced?
There are actually two methods of doing it - stoichimetry & also with the help of law of conservation of mass.
First by stoichiometry:
Now, after balancing the entire equation we get:
So, 1 mole of methane produces 2 moles of water. Hence,
Now by law of conservation of mass:
The entire mass of the reactants will be equal to the entire mass of the products after the reaction.
So, mass of water formed