Given this reaction: #CH_4 + 2O_2 -> CO_2 + H_2O#, 16 g of #CH_4# react with 64 g of #O_2#, producing 44 g of #CO_2#. How many grams of water are produced?

1 Answer
Nov 29, 2016

Answer:

#36# grams of water will get formed.

Explanation:

There are actually two methods of doing it - stoichimetry & also with the help of law of conservation of mass.

First by stoichiometry:

#16#grams of #CH_4# means #1#mole of it.

Now, after balancing the entire equation we get:

#CH_4+2O_2 rarr CO_2+2H_2O#.

So, 1 mole of methane produces 2 moles of water. Hence, #36# grams of water is formed.

Now by law of conservation of mass:

The entire mass of the reactants will be equal to the entire mass of the products after the reaction.

So, mass of water formed #=(16+64)-44# grams, i.e. #36# grams.