# Given v= 2(ab + bc + ca), how do you solve for a?

$\implies v = 2 a b + 2 c a + 2 b c$
$\implies 2 a b + 2 c a = v - 2 b c$
$\implies 2 a \left(b + c\right) = v - 2 b c$
=>a=(v-2bc)/((2(b+c))