Question

Given x2 + (y - 2)2 = 9 is an equation of a circle. What are the coordinates of the center?

Answer 1

center `= (0, 2)`

Explanation:

Given: Equation of a circle: `x^2 + (y - 2)^2 = 9`

Standard form of a circle: `(x- h)^2 + (y - k)^2 = r^2`

where `(h, k)` is the center, and `r =` radius.

If `h = 0` the equation becomes: `x^2 + (y - k)^2 = r^2`

Therefore, the center `= (0, 2)`