# Given y= x ^ { 2} + 2x  , what are the values of y(x) for x = -3, -2, -1, 0, 1, 2 and 3?

May 1, 2018

3, 0, -1, 0, 3, 8, and 15

#### Explanation:

To solve each of these problems, we simply need to plug our given x value into the equation, and find what y equals.

So, for the first one, x=-3, we substitute -3 in for all the x values in our equation.

$y = {\left(- 3\right)}^{2} + 2 \left(- 3\right)$

Then all we have to do is simplify.

$y = 9 - 6 = y = 3$

So our answer when x=-3 is 3.

Let's do one more, how about x=-1?

$y = {\left(- 1\right)}^{2} + 2 \left(- 1\right) = y = 1 - 2 = y = - 1$

So when x=-1, y=-1, meaning our answer here is -1.

To get all the rest of the answers, we use the same method. Just plug in your given number for every x in the equation, and whatever y equals in the end is our answer.