Graph h(x)= x + sin x on [0,2pi]. Explain why the graph appears the way it does?

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Feb 17, 2017

Answer:

graph{x+sinx [-2.87, 17.13, -1.04, 8.96]}

Explanation:

Do you remember the transformtions?
Remember this is the original.
graph{sinx [-10, 10, -5, 5]}
But what appers if I write #sinx+1#
graph{sinx+1 [-10, 10, -5, 5]}
When you add a value in the function this up (+) or down(-)
In this case of #sinx+x# this value is not a constant , is a variable that creates this reazon of this graph.
graph{sinx+x [-3.5, 16.5, -0.32, 9.68]}
Graph of f(x)=x
graph{x [-2, 18, -1.64, 8.36]}

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