Question

Graph (x+2)²+(y-1)²=4. Find the center and radius?

Answer 1

`"centre "=(-2,1)," radius "=2`

Explanation:

`"the equation of a circle in standard form is "`

`color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))`

`"where "(a,b)" are the coordinates of the centre and r"`
`"is the radius"`

`(x+2)^2+(y-1)^2=4" is in this form"`

`"with centre "=(-2,1)" and "r=sqrt4=2`
graph{((x+2)^2+(y-1)^2-4)=0 [-10, 10, -5, 5]}