#H_2SO_4 + 2LiOH -> Li_2SO_4 + 2H_2O# What mass of water is produced from 10 g of sulfuric acid?

1 Answer
Nov 26, 2016

Answer:

Approx. #4*g#.

Explanation:

#"Moles of sulfuric acid"# #=# #(10.0*cancelg)/(98.08*cancelg*mol^-1)=0.102*mol.#

Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.

Given the stoichiometry, #"mass of water"# #=# #0.102*molxx2xx18.01*g*mol^-1=??*g#.

Why did I multiply the mass in this equation by #2#? Am I pulling your leg?