Heather and Matthew walk with an average velocity of 0.98 m/s eastward. If it takes them 34 min to walk to the store, what is their displacement?

1 Answer
Mar 5, 2018

They walked #1999.8 \ "m"~~2 \ "km"#.

Explanation:

Assuming that they also walk #34 \ "min"# east to the store, then the total displacement is calculated as follows.

Displacement is given by the formula

#vecd=vecvxxt#

#v# is the velocity, #t# is the time.

We got: #t=34 \ "min"=2040 \ "s"#

Our #vecv=0.98 \ "m/s"#

So, plugging in the values into the given equation, we get

#vecd=(0.98 \ "m")/(1color(red)cancelcolor(black)"s")*2040color(red)cancelcolor(black)"s"=1999.8 \ "m"#

I would round this number off into #"km"#, in order to make it more reasonable, but this is just my tip.

#1999.8 \ "m"~~2 \ "km"#