# Helium in a 100 mL container at a pressure of 66.6 kPa is transferred to a container with a volume of 250 mL. What is the new pressure if no change in temperature occurs?

Jun 13, 2014

For this problem we would us the equation for Boyle's Law comparing the inverse relationship between pressure and volume when the temperature is held constant.

First we would determine ore known and unknown values from the question.

${P}_{i}$ = 66.6 kPa
${V}_{i}$ = 100 mL
${P}_{f}$ = ???
${V}_{f}$ = 250 mL

${P}_{i} {V}_{i} = {P}_{f}$${V}_{f}$

The equation can be rearranged algebraically to
$\frac{{P}_{i} {V}_{i}}{{V}_{f}} = {P}_{f}$

$\frac{\left(66.6 K P a\right) \left(100 m L\right)}{250 m L}$ = ${P}_{f}$

${P}_{f}$$= 26.6 k P a$