Help me solve and check please?

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2 Answers
Dec 13, 2017

#x=-3#

Explanation:

Remember that #(x*x*x*)^y=x^(3y)#

We know that 27 is the perfect cube of 3.
Therefore,
#27^(2x+1)# becomes #3^(3(2x+1))#

Since the base of the two exponents are now the same, we can cancel them out.

Now, instead of #3^(5x)=3^(3(2x+1))#
We have #5x=6x+3#
#5x=6x+3#
#-x=3#
#x=-3#

Dec 13, 2017

#x=-3#

Explanation:

#"note that "27=3^3#

#rArr3^(5x)=3^(3(2x+1))#

#rArr3^(5x)=3^(6x+3)#

#"since the "color(blue)"bases are 3 on either side"#
#"we can equate the exponents"#

#rArr6x+3=5xrArrx=-3#