Help please?

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1 Answer
Dec 5, 2017

Original expression. #y=x^3-3x#
graph{y=x^3-3x [-5, 5, -5, 5]}

  1. #f(x)# translated three units up. New function is #y=x^3-3x+3#
    graph{y=x^3-3x+3 [-5, 5, -5, 6]}

  2. #f(x)# shifted two places to the left and three places down. New function is #y=(x+2)^3-3(x+2)-3#

graph{y=(x+2)^3-3(x+2)-3 [-5, 5, -8, 5]}

For any value added to #x#, the function is stated as
#(x-"added value")#
For any value subtracted from #x#, the function is stated as
#(x+"subtracted value")#

In case of #y#
For any value added to #y#, the function is stated as
#(y+"added value")#
For any value subtracted from #x#, the function is stated as
#(y-"subtracted value")#

Note the difference of sign in #x# and #y# respectively.

Compare maximum and minimum in the graphs.
Shifting left #-># subtracting amount of shift from #x#
Opposite for shifting right

Shifting up #-># adding amount of shift to #y#
Opposite for shifting down