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1 Answer
maganbhai P.
Mar 6, 2018

#B:theta=0,pi,2pi.#

Explanation:

#5sintheta-4=2sintheta-4rArr3sintheta=0rArrsintheta=0#
#theta=kpi,kinZ# where,#k=0,+-1,+-2,+-3...#
#k=0rArrtheta=color(red)(0in[0,2pi])#
#k=+-1rArrtheta=-pi!in[0,2pi]ortheta=color(red)(piin[0,2pi])#
#k=+-2rArrtheta=-2pi!in[0,2pi]ortheta=color(red)(2piin[0,2pi])#
#k=+-3rArrtheta=+-3pi!in[0,2pi],...,etc.#
Hence, #theta=0,pi,2pi.#

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