Question

Help please?

Answer 1

I consider all the logs in base `10`...

Explanation:

We have:

`log10^36=36log10=36`
and
`-2(10^(log(12)))=-2(12)=-24`

giving: `36-24=12`

Answer 2

The answer is `D`. See explanation.

Explanation:

`log10^36-2*(10^log12)`

If the base of the logarithm is not specified then the base is `10`.

First term: `log10^36` is `36` because you have to raise `10` to the power of `36` to get `10^36`.

The second `log` expression is equal to `12` because for any base `a` it is true that:

`a^{log_a b}=b` ##.

So the expression can be written as:

`log10^36-2*(10^log12)=36-2*12=36-24=12`

The value `12` is the one mentioned in `D`.