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1 Answer
Jim G.
Dec 12, 2017

#(A)log_a((xz^3)/y)#

Explanation:

#"using the "color(blue)"laws of logarithms"#

#•color(white)(x)logx+logy=log(xy)#

#•color(white)(x)logx-logy=log(x/y)#

#•color(white)(x)logx^nhArrnlogx#

#rArr(log_ax-log_ay)+log_az^3#

#=log_a(x/y)+log_az^3#

#=log_a((xz^3)/y)to(A)#

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