Help please?

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1 Answer
Apr 2, 2018

Answer:

#x = 8#

Explanation:

One way to solve #sqrt(3x+1)=x-3# is by squaring both equation terms or

#3x+1 = (x-3)^2#

This operation is responsible for the introduction of strange solutions because solving

#x^2-6x+9 = 3x+1 rArr x^2-9x+8=0# we have

#x^2-6x+9 =(x-1)(x-8)=0# and after substitution in the initial equation we conclude that #x = 1# is not feasible and the solution is #x = 8#