Help solve pls thanks?!

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1 Answer
Gió
Aug 16, 2017

I got #x=a^2#

Explanation:

We can use some properties of logs and the change of base to write:
#log_xa+2log_ax=3#
Change base:
#(log_aa)/(log_ax)+2log_ax=3#
#log_aa-log_ax+2log_ax=3#
#1+log_ax=3#
#log_ax=2#
#x=a^2#

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