# Hi, can i ask what is the differentiate of (1+x^3/2x^2)? Please Thanks thanks for answering my first question :)

differentiation of $\frac{u \left(x\right)}{v \left(x\right)} = \frac{u ' \left(x\right) . v \left(x\right) - v ' \left(x\right) . u \left(x\right)}{v \left(x\right)} ^ 2$
$\frac{6 {x}^{4} - 4 x - 4 {x}^{4}}{4 {x}^{4}}$
$\implies \frac{2 {x}^{4} - 4 x}{4 {x}^{4}}$