Question

Hi can someone help me find this calorie equation?

A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal. When sleeping, the average adult burns or expends about 0.42 Cal/h for every pound of body weight.

How long would the person have to sleep continuously to lose 1 lb of body fat? (Assume the person weighs 165 lb.)
Answer:_h

Answer 1

Chemical energy burnt at the rate of `0.42\ Cal*h^-1` for every pound of body weight

`=>`A `165\ lb` person burns `=0.42xx165 = 69.3 \ Cal*hr^-1`

Given that one pound of body fat stores an amount of chemical energy equivalent to `3500\ Cal`

Number of hours of sleep required to burn `3500\ Cal\ =3500/69.3`

`=50.5\ hr`