Direct variation?

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1 Answer
Feb 15, 2018

see a solution process below;

Explanation:

From the question;

Let, #n = "no of water pumps"#

#t = "time"#

#3n -> 8hrs#

#4n -> xhrs#

Since they flow at same rate therefore, it takes a single pump;

#n = 8/3# pump per hour to fill a pool

For four pumps it would take;

#4n -> 8/3 xx 1/4#

#4n -> 32/12#

#4n -> 3hrs#

Hence it is an inverse variation, because the lesser more the pump, the lesser the time the pool gets filled up..

Hence we have;

#n prop 1/t#

#n =k/t#

Where, #k# is constant..

Initially we have;

#n = 3 and t = 8#

#n = k/t#

#3 = k/8#

#k = 3 xx 8#

#k = 24#

Hence we have;

#n = 24/t#

Making it, the less the #t# value becomes, the more the #n# value..

In other words, the less the time to fill a pool the more the number of pumps vice versa..

In summary

The quantity varies inversely. The constant variation is #24#. Four pumps need #3hrs# to fill a swimming pool..

Hope this helps!