Hi! So i'm having trouble with a problem... I'm studying for EOC and I would appreciate your help! The problem: #x(5x-3)-2x# I've already distributed and I got: #5x^2-3x-2x# which is also equal to #5x^2-5x#... I think no solution?

1 Answer
Jim G.
Apr 1, 2018

#x=0" or "x=1#

Explanation:

#" you have correctly obtained "5x^2-5x#

#"to obtain the solution equate to zero"#

#rArr5x^2-5x=0#

#"take out a "color(blue)"common factor "5x#

#rArr5x(x-1)=0#

#"equate each factor to zero and solve for x"#

#5x=0rArrx=0#

#x-1=0rArrx=1#

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