Question

Ho do I simplify if possible: (x + 1/x) / (2 cosh(ln x)) ?

Answer 1

`(x+1/x)/(2cosh(lnx))=1`

Explanation:

Use the exponential definition of `coshx`:

`coshx = (e^x+e^(-x))/2`

so:

`2cosh(lnx) = (e^(lnx)+e^(-lnx))=(x+1/x)`

and then:

`(x+1/x)/(2cosh(lnx))= (x+1/x)/(x+1/x) = 1`