Hot objects with temperatures of 10 million Kelvin give off most of their radiation in which part of the electromagnetic spectrum?
1 Answer
Jun 14, 2017
Well, this can be estimated with Wien's Displacement Law:
#lambda_(max) = (2.8977729 xx 10^(-3) "m"cdot"K")/T# ,assuming your hot object of interest is a blackbody (not at all related to a woman!), i.e. an opaque body that does not reflect any light.
So, if we assume the surface temperature of the object is
#color(blue)(lambda_(max)) ~~ (2.8977729 xx 10^(-3) "m"cdot"K")/(10^7 "K")#
#= 2.90 xx 10^(-10) "m"#
#=# #color(blue)("0.290 nm")# ,
which is around the X-ray region, with wavelength range