# What is #log_4(2sqrt(2))# ?

##### 1 Answer

Mar 26, 2016

#log_4 (2sqrt(2)) = 3/4#

#### Explanation:

The change of base formula tells us that if

#log_a b = (log_c b) / (log_c a)#

Hence:

#log_4 (2sqrt(2)) = log_2 (2sqrt(2)) / log_2 (4) = log_2 (2^(3/2)) / log_2 (2^2) = (3/2) / 2 = 3/4#