How can I differentiate the function?
H(z)=#ln(sqrt(b^2-z^2)/(b^2+z^2))#
H(z)=
1 Answer
Mar 2, 2018
Explanation:
We want to find the derivative of
#H(z)=ln((sqrt(b^2-z^2))/(b^2+z^2))#
Simplify using the properties of logarithms
Differentiate using the chain rule