How can I draw the following ethers: 1-propoxypentane, 2-ethoxybutane, 1-methoxy-4-chlorohexane, and 3-butoxy-2,4-dimethyloctane?

1 Answer
Jun 16, 2015

You draw the main chain. Then you attach the alkoxy group to the appropriate carbon atom.

Explanation:

1-Propoxypentane

Pentane is a chain of 5 carbon atoms.

The propoxy group is a 3-carbon chain with an "O" atom at "C-1".

Draw a chain of five carbon atoms and attach the 1-propoxy group to "C-1" of the chain.

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2-Ethoxybutane

Attach an ethoxy group to "C-2" of a butane chain.

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4-Chloro-1-methoxyhexane

Draw a 6-carbon chain. Attach a methoxy group to "C-1" and a "Cl" atom to "C-4".

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3-Butoxy-2,4-dimethyloctane

Draw an 8-carbon chain. Attach a butoxy group to "C-3" and methyl groups to "C-2" and "C-4".

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