Question

How can I go about it ?

1. * *

Answer 1

See explanation.

Explanation:

First we have to finf the coordinates of point `A`. To find a point where a function `y=f(x)` crosses the `X` axis we solve the equation `f(x)=0`

`3x-9=0 => 3x=9 => x=3`

So the coordinates of `A` are `A=(3,0)`

The line we are looking for can be written as:

`y=2/3x+c` where `c` is a real constant.

We can use the calculated coordinates of the point `A` to calculate `c`:

`2/3*3+c=0 => c=-2`

The equation of the function is:

`y=2/3x-2`

Now to change the answer to the required form:

1. Move all terms to the left side: `-2/3x+y+2=0`

2. Multiply both sides by `3` to get integer coefficienrs:

`-2x+3y+6=0`