Question

How can I solve this?

`sqrt2cosx-1 = 0`

Answer 1

General Solutions:
`pi/4+ 2pin`
`(7pi)/4+ 2pin`

Where n is an element of all integers.

Explanation:

`sqrt2cosx-1=0`
`sqrt2cosx=1`
`cosx=1/sqrt2`

Let's rationalize the `1/sqrt2` to get a unit circle value:
`1/sqrt2*sqrt2/sqrt2= sqrt2/2`

At what unit circle angles is cos equal to `sqrt2/2`: `pi/4, (7pi)/4`
And what is the period of cos: `2pi`

General Solutions:
`pi/4+ 2pin`
`(7pi)/4+ 2pin`

Where n is an element of all integers.