Question

How can this be solved?

`cos^3xsin^2x = (sin^2x - sin^4x)cosx`

Answer 1

`LHS=cos^3xsin^2x`

`=cos^2xsin^2xcosx`

`=(1-sin^2x)sin^2xcosx`

`=(sin^2-sin^4x)cosx=RHS`