How can we make 10 fold dilution when we only have 0.5 ml of stock solution?
Here's how you can do that.
The idea here is that in a
This is equivalent to saying that the concentration of the stock solution is
In other words, you're performing a
#"DF" = V_"diluted"/V_"stock"" "->#the dilution factor
In your case, you have
#V_"diluted"/V_"stock" = 10 implies V_"diluted" = 10 * V_"stock"#
This means that the volume of the diluted solution must be equal to
#V_"diluted" = 10 * "0.5 mL" = "5 mL"#
So depending on the nature of the substance that you're diluting, you can add enough water to the stock solution to get the total volume to
If you're dealing with a strong acid, you would add the stock solution to enough water to get the total volume of the solution to