How can you evaluate #(2)/(2x+1) + (4)/(x-2) #?

1 Answer
Jun 13, 2018

Put over a common denominator


I assume you mean "How can I put all of this over one fraction?"

Notice that multiplying by a fraction whose numerator and denominator are the same is multiplying by 1, changing nothing. Multiply each fraction by the other denominator in this fashion:

#2/(2x+1)+4/(x-2)=2/(2x+1)(x-2)/(x-2)+4/(x-2) (2x+1)/(2x+1)#