How do find the quotient of # (6x + 9) div (2x + 3)#?

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Answer 1 · 2015-10-28T13:34:59

3

There are two methods that I know of.

One from the old school is to conduct long division. As far as I can ascertain this site's formatting capabilities would make that hard to present.

The other is to factorise and see if we can cancel out.

Lets try the latter:

Write as:

#(6x+9)/(2x+3)#

But #6x+9 = 3(2x+3)#

Substitute giving:

#(3(2x+3))/(2x+3)#

#3 times (2x+3)/(2x+3)#

but

#(2x+3)/(2x+3) =1#

leaving just 3 as the answer