# How do find the quotient of (x^2-3x+2) div (x-1)?

$x - 2$
$\left({x}^{2} - 3 x + 2\right) \div \left(x - 1\right)$
$= \left({x}^{2} - x - 2 x + 2\right) \div \left(x - 1\right)$
$= \left(x \left(x - 1\right) - 2 \left(x - 1\right)\right) \div \left(x - 1\right)$
$= \left(x - 1\right) \left(x - 2\right) \div \left(x - 1\right)$
$= x - 2$