# How do find the vertex and axis of symmetry, and intercepts for a quadratic equation #y=3(x-3)^2+4#?

##### 1 Answer

Jun 4, 2015

graph{3x^2 - 18x + 31 [-10, 10, -5, 5]}

This function y is written the vertex form

x of vertex: x = 3

y of vertex y = 4

Axis of symmetry: x = 3

x- intercepts -> Find the standard form

There are no real roots (no x- intercepts). The graph is completely above the x axis