Question

How do I figure out the following problem...How many moles of HCl are in 10.5 mL of a 12 M HCl solution ?

Answer 1

`"0.126 mol"`

Explanation:

Fromula for Molarity is

`"Molarity" = "Moles of solute"/"Volume of solution (in litres)"`

`"12 M" = "n"/"0.0105 L"`

`"n = 12 M × 0.0105 L"\ = color(green)"0.126 mol"`