Question

How do I figure this out? Thanks

Answer 1

Smaller diagonal is `4.453` and longer diagonal is `10`

Explanation:

If the two sides of a parallelogram are `a` and `b` and acute angle between the sides is `theta`,

the smaller diagonal is `sqrt(a^2+b^2-2abcostheta)`

and longer diagonal is `sqrt(a^2+b^2+2abcostheta)`

Hence in the given case

Smaller diagonal is `sqrt(3.7^2+6.8^2-2xx3.7xx6.8xxcos48^@`

= `sqrt(13.69+46.24-50.32xx0.66913)`

= `sqrt(59.93-40.101)`

= `sqrt19.829`

= `4.453`

Longer diagonal is `sqrt(3.7^2+6.8^2+2xx3.7xx6.8xxcos48^@`

= `sqrt(13.69+46.24+50.32xx0.66913)`

= `sqrt(59.93+40.101)`

= `sqrt100.031`

= `10`