What is the derivative of #f(x)=(e^(1/x))/x^2# ? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Wataru Sep 20, 2014 By Quotient Rule, #f'(x)={-1/x^2e^{1/x}cdot x^2-e^{1/x}cdot2x}/{(x^2)^2}# by cancelling out #x^2# in the numerator, #={-e^{1/x}-2xe^{1/x}}/{x^4}# by factoring out #-e^{1/x}# from the numerator, #=-{(1-2x)e^{1/x}}/{x^4}# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? How do you find the derivative of #y=e^(5x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 11986 views around the world You can reuse this answer Creative Commons License