How do I find the base of an isosceles triangle if the legs are 8x-4 and 5x+11 And the base is 4x-2?

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Answer 1 · 2018-03-04T03:30:05

Given the legs of isosceles triangle are 8x-4 and 5x+11.

So #8x-4=5x+11#

#=>8x-5x=11+4#

#=>3x=15#

#=>x=15/3=5# unit

Now base of the triangle

#=4x-2=4*5-2=18# unit.