How do I find the range of these functions without using a graph #y=-2+sqrt(16-x^2)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Sonnhard Jun 9, 2018 #-2<=-2+sqrt(16-x^2)<=2# Explanation: Since #sqrt(16-x^2)>=0# we get #-2<=-2+sqrt(16-x^2)# Since #-x^2<=0# we get #sqrt(16-x^2)<=4# or #-2+sqrt(16-x^2)<=2# Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1406 views around the world You can reuse this answer Creative Commons License