How do I find the restricted values of x?: 6x/8x^2-7x

1 Answer
Mar 18, 2018

#x≠0# #x≠7/8#

Explanation:

#(6x)/(8x^2-7x)#

Here's a graph before we calculate the restricted values of x algebraically:
graph{6x/(8x^2-7x) [-10.89, 15.41, -4.84, 8.31]}

The denominator of the rational function can never be equal to 0:
So therefore these values would make the function undefined:
#8x^2-7x=0#
#x(8x-7)=0#
#x≠0# #x≠7/8#

Futhermore #x≠0# should be a removable discontinuity, and would show up as a hole on the graph, rather than a vertical asymptote.