How do I find the vertex, axis of symmetry, y-intercept, x-intercept, domain and range of #y=-2x^2-8x+3#?
Vertex(-2,11). Axis of symmetry x= -2
Y intercept is 3, x intercepts are
Complete the square for x as follows:
This gives vertex (-2, 11) axis of symmetry x=-2,
For y intercept put x=0 in the given equation to get y=3. For x intercept put y= 0 to get
quadratic formula x=
The parabola opens downwards because of negative coefficient of