# How do I find the vertex, axis of symmetry, y-intercept, x-intercept, domain and range of y=2(x+3)^2+6?

Sep 25, 2015

Vertex (-3,6),axis of symmetry x= -3,domain is R(set of real numbers) and Range is [6,infinite) graph{2(x+3)^2 +6 [-25.09, 20.51, -2.37, 20.43]}

#### Explanation:

On simplifying the equation,we have $\frac{y - 6}{2}$ = ${\left(x + 3\right)}^{2}$
which represents a parabola.
Using $\frac{y - 6}{2}$ = $0$,y=6
and ${\left(x + 3\right)}^{2}$ = 0,x=-3
Thus,vertex of parabola is $\left(- 3 , 6\right)$
Moreover,it is symmetric about its axis $x + 3 = 0$