# How do I graph the hyperbola with the equation #4x^2−y^2+4y−20=0?#?

##### 1 Answer

Aug 14, 2018

Please see the explanation below

#### Explanation:

You need the center, the vertices and the asymptotes.

The equation is

Dividing by

Comparing this to the general equation of a hyperbola

The center is

The vertices are

and

And the asymptotes are

Now, you can plot the graph

graph{(4x^2-y^2+4y-20)(y-2-2x)(y-2+2x)=0 [-15.77, 16.27, -5.8, 10.2]}